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26 replies   7836 views
2

Description

Description by BillyMaysed
5

Can be used to make Runewords:

7
Beardozer wrote: 2 years ago
Either 1.4 thousand years, or 1.3 million years. Quite the spread there.
Well, I did check the math and it is definitely closer to 1.3m than 1.4k.
7
User avatar

geo89 50

Assassin Americas XLinux
(3^20)^13 = 3^260 = 1.12596846425e+124

no recipe for
El
, so there are 20 runes that need 3 like runes to transmute, each rune is 3^1, 3^2, 3^3 ... 3^n respectively. Then we need each one of those for a
Pul
rune which is the new base in the 2fer formula, there are twelve 2fer runes to get to
Zod
but the second exponent is actually a 13 because (3^20)^1 gets you 1
Pul
, (3^20)^2 gets you
Um
and so forth, so continuing to
Zod
you get the the exponent of 13. (3^20)^13 = 1.12596846425e+124.

EDIT: whoops I way overdid this problem and arrived to an incorrect answer. OP is right; 3^20 =
El
to
Pul
, 2^12 =
Pul
to
Zod
, multiply the two to get 14 trillion 281 billion 868 million 906 thousand 496 or about 48 times the estimated amount of stars in our galaxy, good luck!

This is a HARDCORE trade. PC only.
7
aight now we need to know how many mules and accs you need to STORE all runes :D

check for more stuff right here


Please offer on here not though private messages.
I don't like trying to haggle with people on PM.
7
Lets make a game "
El
Dumpster" to get this startet anyone is without plans for the next few decades?
7
BillyMaysed wrote: 2 years ago
Necroing this thread because math.
Necroing this thread because of necromancy.

Before proceding i want to present OP's math in what i hope is a more readable form.

For reference let's use this page as it contains and index for each rune. Let's denote #X a variable describing the index of a rune.

Take Runes #2 (
Eld
) and #3 (
Tir
).
  • And
    Eld
    rune is 3^1
    El
    runes and is #2
  • And
    Tir
    rune is 3^2
    El
    runes and is #3
From that we deduce that, up to a
Pul
rune, the number of
El
runes to get rune #X is:

3^(X-1) El runes

Pul
is #21. So a
Pul
rune = 3^20 El runes

After that we need to multiply by powers of two. Similarly
  • Um
    is 2^1 Puls and is #22
  • Mal
    is 2^2 Puls and is #23
So, from
Um
to
Mal
, the number of
Pul
runes to get to rune #Y is:

2^(Y-21) Pul runes

Zod
is #33 So putting both together:

3^19 * 2^(33-21) = 14,281,868,906,496

Or 14 trillion, 281 billion, 868 million, 906 thousand and 496
El
runes
.
Lastly, let's have some fun.

Okay, so what does it say to players? Not much. There are 33 runes in this game - no one is trying to cube
El
up to a
Zod
.

Let's take the Cow Level. Conveniently enough it is packed with lots hell cows and a regular (white)
Hell Bovine
can drop up to a
Zod
. So our parameter for drop chances will be a white
Hell Bovine
. Let's assume a reasonable 5 minute length for a cow run in players 7 and an average of 400 cows per lvl. So 5 minutes = 400 cows. Let's ignore the champion and unique cows for simplicity.

Let's call D the drop chance of a chosen rune from a single white cow. Consequently the chance for getting said rune a given run is about 400*D.

So the number of runs expected for a single drop is:

(400*D)^1

Let's pretend rune X has a 1 in 800 chance to drop from a white cow. Given our 400 cows/run:

(400/800)^1 = 800/400 = 2 runs per drop

Lastly, to get our time per drop in hours we multiply by 5 min and divide by 60 min/h.
Rune Drop Chance (1 in #) Runs per drop hours per drop
Gul
110,669 276.67 23.06
Vex
166,003 415 34.58
Ohm
157,580 393.95 32.83
Lo
236,370 590.93 49.24
Sur
213,077 532.69 44.39
Ber
319,615 799.04 66.59
Jah
286,200 715.5 59.63
Cham
429,300 1073.25 89.44
Zod
1,120,383 2800.96 233.41
As you can see the number of runes to cube grows exponentially but drop chances are a hell of a mess grows waaay slower and even with some non-linearities.

You would need 8
Gul
runes to cube up to a
Lo
. That is about 23.06*8=184,48 hours of playtime, while a
Lo
rune is about "only" 49.24 hours. If cubing were to follow drop chance, a
Lo
rune would be about 2
Gul
runes.

Lession learned? Cubing high runes is HIGHLY inefficient in terms of drop times. So only do it if you can get a lot of value out of it in the form of making that Runeword you've always wanted and/or you will get a lot of trade value out of it. Trading is highly non-linear ;)

Once i get some more free time I'll post some graphics.
7
wow, almost exact number of
El
i found so far (too bad, did not pick all them) :D

Add on Bnet for faster checkout -- SleepyShaman#23358
7
ladydorcas wrote: 2 years ago
aight now we need to know how many mules and accs you need to STORE all runes :D
That is an easy answer since we know open slots for each character and shared stash.

Each stash tab is 100 slots, inventory is 40 slots. We can gain 8 slots (takes 2*2, gives 4*3) if we use cube. So, shared stash holds 300 slots and account with 20 characters holds exactly 2960 slots (with cube), so 3260 slots per account.

Divide needed runes by slots per account and we get =4,380,941,382.36 or 4,380,941,383 (nearly 4.4 billion) accounts if rounded up.

Also need same amount of cubes.

This is not conclusive answer though since we need to store gems, too.
9

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