Well, I did check the math and it is definitely closer to 1.3m than 1.4k.Beardozer wrote: 3 years ago Either 1.4 thousand years, or 1.3 million years. Quite the spread there.
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Description by BillyMaysedCan be used to make Runewords:
(3^20)^13 = 3^260 = 1.12596846425e+124
no recipe for El, so there are 20 runes that need 3 like runes to transmute, each rune is 3^1, 3^2, 3^3 ... 3^n respectively. Then we need each one of those for a Pul rune which is the new base in the 2fer formula, there are twelve 2fer runes to get to Zod but the second exponent is actually a 13 because (3^20)^1 gets you 1 Pul, (3^20)^2 gets you Um and so forth, so continuing to Zod you get the the exponent of 13. (3^20)^13 = 1.12596846425e+124.
EDIT: whoops I way overdid this problem and arrived to an incorrect answer. OP is right; 3^20 = El to Pul, 2^12 = Pul to Zod, multiply the two to get 14 trillion 281 billion 868 million 906 thousand 496 or about 48 times the estimated amount of stars in our galaxy, good luck!
no recipe for El, so there are 20 runes that need 3 like runes to transmute, each rune is 3^1, 3^2, 3^3 ... 3^n respectively. Then we need each one of those for a Pul rune which is the new base in the 2fer formula, there are twelve 2fer runes to get to Zod but the second exponent is actually a 13 because (3^20)^1 gets you 1 Pul, (3^20)^2 gets you Um and so forth, so continuing to Zod you get the the exponent of 13. (3^20)^13 = 1.12596846425e+124.
EDIT: whoops I way overdid this problem and arrived to an incorrect answer. OP is right; 3^20 = El to Pul, 2^12 = Pul to Zod, multiply the two to get 14 trillion 281 billion 868 million 906 thousand 496 or about 48 times the estimated amount of stars in our galaxy, good luck!
This is a HARDCORE trade. PC only.
aight now we need to know how many mules and accs you need to STORE all runes
Please offer on here not though private messages.
I don't like trying to haggle with people on PM.
Lets make a game " El Dumpster" to get this startet anyone is without plans for the next few decades?
Necroing this thread because of necromancy.
Before proceding i want to present OP's math in what i hope is a more readable form.
For reference let's use this page as it contains and index for each rune. Let's denote #X a variable describing the index of a rune.
Take Runes #2 ( Eld) and #3 ( Tir).
From that we deduce that, up to a Pul rune, the number of El runes to get rune #X is:
3^(X-1) El runes
Pul is #21. So a Pul rune =
3^20 El runes
After that we need to multiply by powers of two. Similarly
So, from Um to Mal, the number of Pul runes to get to rune #Y is:
2^(Y-21) Pul runes
Zod is #33 So putting both together:
3^19 * 2^(33-21) = 14,281,868,906,496
Or 14 trillion, 281 billion, 868 million, 906 thousand and 496 El runes.
Lastly, let's have some fun.
Okay, so what does it say to players? Not much. There are 33 runes in this game - no one is trying to cube El up to a Zod.
Let's take the Cow Level. Conveniently enough it is packed with lots hell cows and a regular (white) Hell Bovine can drop up to a Zod. So our parameter for drop chances will be a white Hell Bovine. Let's assume a reasonable 5 minute length for a cow run in players 7 and an average of 400 cows per lvl. So 5 minutes = 400 cows. Let's ignore the champion and unique cows for simplicity.
Let's call D the drop chance of a chosen rune from a single white cow. Consequently the chance for getting said rune a given run is about 400*D.
So the number of runs expected for a single drop is:
(400*D)^1
Let's pretend rune X has a 1 in 800 chance to drop from a white cow. Given our 400 cows/run:
(400/800)^1 = 800/400 = 2 runs per drop
Lastly, to get our time per drop in hours we multiply by 5 min and divide by 60 min/h.
As you can see the number of runes to cube grows exponentially but drop chances are a hell of a mess grows waaay slower and even with some non-linearities.
You would need 8 Gul runes to cube up to a Lo. That is about
23.06*8=184,48 hours
of playtime, while a Lo rune is about "only" 49.24 hours
. If cubing were to follow drop chance, a Lo rune would be about 2 Gul runes.Lession learned? Cubing high runes is HIGHLY inefficient in terms of drop times. So only do it if you can get a lot of value out of it in the form of making that Runeword you've always wanted and/or you will get a lot of trade value out of it. Trading is highly non-linear
Once i get some more free time I'll post some graphics.
wow, almost exact number of El i found so far (too bad, did not pick all them)
Add on Bnet for faster checkout -- SleepyShaman#23358
That is an easy answer since we know open slots for each character and shared stash.ladydorcas wrote: 2 years ago aight now we need to know how many mules and accs you need to STORE all runes
Each stash tab is 100 slots, inventory is 40 slots. We can gain 8 slots (takes 2*2, gives 4*3) if we use cube. So, shared stash holds 300 slots and account with 20 characters holds exactly 2960 slots (with cube), so 3260 slots per account.
Divide needed runes by slots per account and we get =4,380,941,382.36 or 4,380,941,383 (nearly 4.4 billion) accounts if rounded up.
Also need same amount of cubes.
This is not conclusive answer though since we need to store gems, too.
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