The Great Annihilus Guessing Game [SC NON-Ladder]

My guess is

2 of each 20 20 - 5 to 10 exp = 6 different

Annihilus
2 of each 20 19 - 5 to 10 exp.. 6 more
2 of each 20 18 - 5 to 10 exp.. 6 more
2 of each 20 17 - 5 to 10 exp.. 6 more
2 of each 20 16 - 5 to 10 exp.. 6 more
2 of each 20 15 - 5 to 10 exp.. 6 more
2 of each 20 14 - 5 to 10 exp.. 6 more
2 of each 20 13 - 5 to 10 exp.. 6 more
its 48 combinations and 2 remaining are:
2 of 10/10/5

btw it's an interesting mathematical puzzle because, on average, 1.2 of each should appear for each combination, so it would seem that you would have to bet on 1 case of 50 different outcomes, assuming that one of each will appear. However, since the correct value gives a number of points equal to that value, you have a better chance of winning by betting on two of each rather than one. The difference isn't large, but noticeable.

Betting on one of each will yield an average of 18.11 points, and betting on two of each will yield 21.73 points.

But this is a relatively small sample, and the deviations can be significant.